How much tangential force would be needed to stop the earth in one year, if it were rotating with angular velocity of `7.3 xx 10^(-5) "rad s"^(-1)` ? Given the moment of inertia of the earth `=9.3 xx 10^(37) "kg m"^(2)` and radius of the earth `=6.4 xx 10^(6)` m.

How much tangential force will be needed to stop the earth in one year, if it is rotating with an angular velocity of 7.3 xx 10^(-5) rad//s ? Given moment of inertia of earth = 9.3 xx 10^(37) kg m^(2) and radius of earth = 6.4 xx 10^(6) m .

The earth is rotating with an angular velocity of 7.3 xx 10^(-5) rad/s. What is the tangential force needed to stop the earth in one year ? Given moment of inertia of the earth about the axis of rotation = 9.3 xx 10^(37) m^(2) . Radius of the earth = 6.4 xx 10^(6) m

Calculate the acceleration due to gravity on the earth from the following data G= 6.6 xx 10 ^(-11) N m^(2) Kgm^(-3) Mean density of the earth = 5xx 10 ^(-3) kgm Radius of the earth = 6.4 xx10 ^(6) m .

Find the escape velocity of a body from the surface of the earth. Given radius of earth = 6.38 xx 10^(6) m .

Calculate the mass of the earth. Given radius of the earth =6.4xx10^-6 m and g = 9.8 m//s^2

The earth (mass = 10^(24) kg) revolves round the Sun with an angular velocity 2 xx 10^(-7) rad s^(-1) in a circular orbit of radius 1.5 xx 10^(8)km . Find the force exerted by the Sun on the earth (in xx 10^(21)N) .

The earth (mass = 10^(24) kg) revolves round the Sun with an angular velocity 2 xx 10^(-7) rad s^(-1) in a circular orbit of radius 1.5 xx 10^(8)km . Find the force exerted by the Sun on the earth (in xx 10^(21)N) .

What is the magnitude of the gravitational force between the earth and a 1 kg object on its surface? (Mass of the earth is 6 xx 10^(24) kg and radius of the earth is 6.4 xx 10^(6) m. )