The sum of the digits of a two-digits number is 5 and their difference is 3. Find the number. The following are the steps involved in solving the above problem. Arrange them in sequential order.
(A) `x+ y =5 and x-y =3`
(B) Let the number be `xy`
(C) The required number is 41.
(D) `x =4 and y =1`
(E) Solving `x +y = 5 and x -y =3`

The sum of predecessors of two numbers is 36 and their difference is 4. Find the numbers. The following are the steps involved in solving the above problem. Arrange them in sequential order (A) X - 1 + Y -1 = 36 and X -Y =4 (B) Solve for X and Y (C) Let X gt Y (D) Let the number be X and Y

The following sentences are the steps involved in solving 4-3x lt 5 . Arrange them in sequential order, (A) -3x lt 1 (B) -x lt 1//3 (C) -3x lt 5 -4 (D) x gt -1//3

There are two number. The predecessor of the larger number exceeds the successor of the smaller number by 6. The sum of the numbers is 32. Find the numbers The following are the steps involved in solving the above problem. Arrange them in sequential order. (A) M + N = 32 and M -1 - (N +1) = 6 (B) Let N lt M (C) Solve for M and N (D) Let of numbers be M and N

The sum of the digits of a two-digit number is 11. if 9 is subtracted from the number, then the digits interchagne their places. Find the number. The following steps are involved in solving the above problem. Arrange them in sequential order (A) Let the units digit be x. therefore , the tens digit is (11-x). therefore The number is 10(11-x)+x=110-9x . (B) Given that 110-9x-9=9x+11rArrx=5 . (C) Units digit is S and tens digit is 6 and the required number is 65. (D) The number formed by interchanging the digits is 10x+(11-x)=9x+11 .

The sum of the digits of a two-digit number is 12. if 18 is subtracted from the number, then the digits interchange their places. Find the number. The following steps are involved in solving the above problem. Arrange them in sequential order. (A) Units digits is 5, tens digit is 7, and the number is 75. (B) Given that 120-9x-18=9x+12rArr90=18xrArrx=5 . (C) The number formed by interchanging the digits is 10x+(12-x)=9x+12 . (D) Let the digit in the units place be x. Then the digit in the tens place be (12-x). therefore The number is 10(12-x)+x=120-10x+x=120-9x .

Two-third of a certain number exceeds one-third of the number by 10. Find the number. The following steps are involved in solving the above problem. Arange them in sequential order (A) (2x)/(3) - (x)/(3) = 10 (given) (B) (2x -x)/(3) = 10 rArr (x)/(3) = 10 (C) rArr x = 30 (D) Let the number be x