Line `x+y=2` is tangent to the curve `x^(2)=3-2y` at the point

The line y = x + 2 , is a tangent to the curve y^2 = 4x at the point :

If lines T_(1) and T_(2) are tangent to the curve y=x^(2)-3x+2 at the points where the curve meets the X- axes , then

The slope of the tangent to the curve y=x^(2) -x at the point where the line y = 2 cuts the curve in the first quadrant, is

The slope of the tangent to the curve y=x^(2) -x at the point where the line y = 2 cuts the curve in the first quadrant, is

Equation of the tangent to the curve y=2x^(2)+5x , at the point where the line y=3 cuts the curve in the first quadrant , is

Equation of the tangent to the curve y=2-3x-x^(2) at the point where the curve meets the Y -axes is

Find the equation of the tangent line to the curve : y=x^(3)-3x+5 at the point (2, 7)

The slope of the tangent line to the curve x+y=xy at the point (2,2) is

Find the equations of the tangent line to the curve: y = 2x^2 + 3y^2 = 5 at the point (1,1)