For a body travelling with uniform acceleration,its final velocity `v=sqrt(180-7x)` ,where x is the distance travelled by the body.Then the acceleration is

The distance travelled by the moving body is :

The shortest distance travelled by a body is called its

In the given v-t graph the distance travelled by the body in 5 seconds will be

In the given v-t graph, the distance travelled by the body in 5 sec will be :

Assertion : Distance-time graph of the motion of a body having uniformly accelerated motion is a straight line inclined to the time axis. Reason : Distance travelled by a body having uniformly accelerated motion is directly proportional to the square of the time taken.

A particle starts moving in a straight line from rest with an acceleration ("in"m//s^(2) ) given by : a=12 sqrt x , where x is the distance travelled by the particle (in meters ) The velocity of the particle at the instant when its acceleration is 48m//s ^(2) is .......m//s

A body starting from rest is moving with a uniform acceleration of 8m/s^(2) . Then the distance travelled by it in 5th second will be

For body moving with uniform acceleration a , initial and final velocities in a time interval t are u and v respectively. Then its average velocity in the time interval t is