Home
Class 11
CHEMISTRY
Statement-1 : When 40 gm of NaOH is mixe...

Statement-1 : When 40 gm of NaOH is mixed with 49gm `H_2SO_4` and mixed with water then 89gm of `NaSO_4` is obtained assuming `100%` yield.
Statement-2 : For producing maximum amount of `Na_2SO_4` with `100%` yield NaOH and `H_2SO_4` should be present in a molar ratio of `2:1`.

Promotional Banner

Similar Questions

Explore conceptually related problems

Weight of H_2SO_4 in gm required to neutralize 40 gm of NaOH .

100 ml of 0.1 N NaOH is mixed with 50 ml of 0.1 N H_2SO_4 . The pH of the resulting solution is

100 mL of 1N H_2SO_4 is mixed with 100 mL of 1M NaOH solution. The resulting solution will be

10 gm NaOH and 9.8 gm H_(2)SO_(4) are allowed to react by which 8.52 gm Na_(2)SO_(4) is formed. The percentage yield of products is -

10 gm NaOH and 9.8 gm H_(2)SO_(4) are allowed to react by which 8.52 gm Na_(2)SO_(4) is formed. The percentage yield of products is -

What weight of 98% pure H_(2)SO_(4) is required to neutralize 80gm of NaOH ?

What weight of 98% pure H_(2)SO_(4) is required to neutralize 80gm of NaOH ?