If `omega` is a cube root of unity , then `|(x+1 , omega , omega^2),(omega , x+omega^2, 1),(omega^2 , 1, x+omega)|` =

If omega is a cube root of unit, then Delta=|(x+1,omega, omega^(2)),(omega, x+omega^(2),1),(omega^(2),1,x+omega)|=

If omega ne 1 is a cube root of unity, then 1, omega, omega^(2)

Select and write the correct answer from the given alternatives in each of the following:If omega is a cube root of unity,then for the equations |(x+1,omega,omega^2),(omega,x+omega^2,1),(omega^2,1,x+omega)|=0 ,x=

If omega is a cube root of unity |(1, omega, omega^(2)),(omega, omega^(2), 1),(omega^(2), omega, 1)| =

If omega is the cube root of unity then {:abs((1,omega,omega^2),(omega,omega^2,1),(omega^2,1,omega)):} is

If omega is cube root of unity, then a root of the equation |(x + 1,omega, omega^2),(omega, x + omega , 1),(omega^2 , 1, x + omega)| = 0 is