The volume of an air bubble becomes 8 times the original volume in rising from the bottom of a lake to its surface. If the barometice height is 0.76 m of mercury (density of mercury is `13.6 g cm^(-3) and g = 9.8 ms^(-2))` what is the depth of the lake ?

(a) A spherical tank of 1.2m radius is half filled with oil of relaive density 0.8 . If the tank is given a horizontal acceleration of 10m//s^(2) . Calculate the inclination of the oil surface to horizontal and maximum pressure on the tank. (b) The volume of an air bubble is doubled as it rises from the bottom of a lake to its surface. If the atmospheric pressure is H m of mercury & the density of mercury is n times that of lake water. Find the depth of the lake.

What volume will 250 g of mercury occupy ? (Density of mercury =13.6 g cm^(-3) )

The volume of an air bubble increases by x% as it raises from the bottom of a water lake to its surface. If the water barometer reads H , the depth of the lake is

The volume of an air bubble becomes three times as it rises from the bottom of a lake to its surface. Assuming atmospheric pressure to be 75 cm of Hg and the density of water to be 1//10 of the density of mercury, the depth of the lake is

The volume of an air bubble becomes three times as it rises from the bottom of a lake to its surface. Assuming atmospheric pressure to be 75 cm of Hg and the density of water to be 1//10 of the density of mercury, the depth of the lake is

An air bubble doubles in radius on rising from the bottom of a lake to its surface. If the atmospheric pressure is equal to that of a column of water of height H, the depth of lake is

Calculate the pressure at the bottom of a fresh water lake of depth 10 m. The atmospheric pressure = 76 cm of mercury and the density of mercury = 13.6g*cm^(-3) .

An air bubble doubles in radius on string from the bottom of a lake to its surface. If the atmospheric pressure is equal to that of a column of water of height H , the depth of the lake is