IF ` tan theta _1 = k cot theta _2 ,` then `( cos ( theta _1+ theta _2))/(cos ( theta _1 - theta_2))`=

If cos theta _(1) = 2 cos theta _(2), then tan (( theta _(1) + theta _(2))/(2)) tan (( theta _(1) - theta _(2))/(2)) is equal to

if tan theta_(1)=k cot theta_(2) then find (cos(theta_(1)-theta_(2)))/(cos(theta_(1)+theta_(2)))=

If ( cos ( theta_1- theta_ 2 ))/(cos ( theta_1+ theta_2))+( cos ( theta_3 + theta_4))/( cos ( theta_3- theta_4))=0 , then tan theta_1 , tan theta_2 tan thet_3 tan theta_4=

If tan theta_(1).tantheta_(2)=k , then: (cos(theta_(1)-theta_(2))/(cos(theta_(1)+theta_(2)))=

(sin^(2) theta )/(1- cot theta )+(cos^(2) theta )/( 1- tan theta ) =

(cos theta)/(cos ec theta+1)+(cos theta)/(cos ec theta-1)=2tan theta

Prove that (1+ cot theta + tan theta ) ( sin theta - cos theta) = (sec theta )/(cosec^(2) theta) - (cosec theta)/(sec^(2)theta) .

Prove that (cot theta -cos theta )/( cot theta +cos theta ) =(cos ec theta -1)/( cosec theta +1)

Prove that (cot theta -cos theta )/( cot theta +cos theta ) =(cos ec theta -1)/( cosec theta +1)

Prove that (cot theta -cos theta )/( cot theta +cos theta ) =(cos ec theta -1)/( cosec theta +1)