If `x=sqrt(6) and y^(2)=12`, then `(4)/(xy)=`

(sqrt(x)+sqrt(y))^(2)=x+y+2sqrt(xy) and sqrt(x)sqrt(y)=sqrt(xy) , where x and y are positive real numbers . If x=2sqrt(5)+sqrt(3) and y=2sqrt(5)-sqrt(3) , then x^(4)+y^(4) =

If x + y = 1 and xy(xy - 2) = 12, then the value of x^4+y^4 is: यदि x + y = 1 और xy(xy - 2) = 12, है, तो x^4+y^4 का मान क्या होगा ?

If y=e^(sqrt(x))(sqrt(x)-1)," then "4xy_(2)-2y_(1)=

If y=e^(sqrt(x))+e^(-sqrt(x))," then "4xy_(2)+2y_(1)=

The solution (x,y) of the system of equations x-y=(1)/(6) and cos^(2)(pi x)-sin^(2)(xy)=(sqrt(3))/(4) is given by

Find the angle of intersection of the following curves: xy=6 and x^(2)y=12y^(2)=4x and x^(2)=4y

x + y = (4)/(sqrt3) and x - y = (2)/(sqrt3) , then the value of 4xy is