In an acute angled triangle `ABC`, let `AD, BE` and `CF` be the perpendicular opposite sides of the triangle. The ratio of the product of the side lengths of the triangles `DEF` and `ABC`, is equal to

In an acute angle Delta ABC, let AD, BE and CF be the perpendicular from A, B and C upon the opposite sides of the triangle. (All symbols used have usual meaning in a tiangle.) The circum-radius of the Delta DEF can be equal to

In an acute angle Delta ABC, let AD, BE and CF be the perpendicular from A, B and C upon the opposite sides of the triangle. (All symbols used have usual meaning in a tiangle.) The circum-radius of the Delta DEF can be equal to

In an acute angle Delta ABC, let AD, BE and CF be the perpendicular from A, B and C upon the opposite sides of the triangle. (All symbols used have usual meaning in a tiangle.) The orthocentre of the Delta ABC, is the

In an acute angle Delta ABC, let AD, BE and CF be the perpendicular from A, B and C upon the opposite sides of the triangle. (All symbols used have usual meaning in a tiangle.) The orthocentre of the Delta ABC, is the

In an acute angle triangle ABC, AD, BE and CF are the altitudes, then (EF)/a+(FD)/b+(DE)/c is equal to -

In an acute angle triangle ABC, AD, BE and CF are the altitudes, then (EF)/a+(FD)/b+(DE)/c is equal to -

AD,BE and CF are the perpendiculars from the angular points of a Delta ABC upon the opposite sides.The perimeters of the Delta DEF and Delta ABC are in the ratio-

In an acute angle triangle ABC,AD,BE and CF are the altitudes,then (EF)/(a)+(FD)/(b)+(DE)/(c) is equal to -