The first line of the lyman series in a hydrogen spectrum has a wavelength of 1210 Å. The corresponding line of a hydrogen like atom of `Z=11` is equal to

The wave number of the first line in the Lyman series in hydrogen spectrum is

The wavelength of the first line of the Balmer series of hydrogen atom is lamda . The wavelength of the corresponding line line of doubly ionized lithium atom is

The second member of Lyman series in hydrogen spectrum has wavelength 5400 Å . Find the wavelength of first member.

The frequency of the first line of the Lyman series in the hydrogen atom is nu . What will be the frequency of the corresponding line for the singly ionised helium atom ?

First line of Lyman series of hydrogen atom occurs at lamda=x Ã…. The corresponding line of He^(+) will occur at:

The wavelength of the first spectral line of the Lyman series of hydrogen spectrum is

The frequency of the first line in Lyman series in the hydrogen spectrum is v. What is the frequency of the corresponding line in the spectrum of doubly ionized Lithium?