A body of mass 12 kg is suspended by a coil spring of natural length 50 cm and force constant `2.0xx10Nm^(-1)`. What is the stretched length of the spring ? If the body is pulled down further stretching the spring to a length of 59 cm and then released, what is the frequency of oscillation of the suspended mass ? (Neglect the mass of the spring).

A body of mass 10 kg is suspended by a massless coil spring of natural length 40 cm and force constant 2.0xx10^(3)Nm^(-1) . What is stretched length of the spring.? If the body is pulled down further stretching the spring to a length 48cm and then released, what is the frequency of oscillations of the suspended mass ? g=10ms^(2)

A coil of natural length 40 cm and K = 10^(3) N m is used to suspend of a mass of 10 kg from its one end. (i) calculate the stretched length of the coil. (ii) If the mass is further pulled down by stretching the coil to a length of 46 cm and then released, then calculate the frequency of oscillation of the suspended mass ? (Consider spring to be massless)

A body of mass 100 gram is suspended from a light spring which stretches it by 10 cm. Find the force constant of the spring.

A body of mass 100 gm is suspended from a light spring which stretches it by 10 cm. Find the force constant of the spring.

A spring has a natural length of 50 cm and a force constant 2 xx 10^3N/m . A body of mass 10 kg is suspended from it and the spring is stretched . If the body is pulled down further stretching the string to a length of 58 cm and released, it executes simple harmonic motion. The force on the body when it is at its lowermost position of oscillation will be

A body of mass m is suspended from a massless spring of natural length l . It stretches the spring through a vertical distance y . The potential energy of the stretched spring is

A body of mass 1 kg suspended by a light vertical spring of spring constant 100 N/m executes SHM. Its angular frequency and frequency are