The equation `2cos^2x/2sin^2x=x^2+x^(-2);0`

The equation 2cos^2(x/2)sin^2x=x^2+x^(-2);0 <= x <=pi/2 has

The equation 2cos^2 (x/2)sin^2x=x^2+x^(-2);0

The equation 2cos^2 (x/2)sin^2x=x^2+x^(-2);0

The equation 2cos^2(x/2)sin^2x=x^2+x^-2, 0ltxlepi/2 has (A) no real solution (B) one real solution (C) two real solutions (D) more than two rea solutions

The equation 2cos^(2)(x/2) sin^2x=x^(2)+x^(-2), 0 lt x^(-2), 0 lt x le pi/2 has

The equation 2(cos^(2)x)/(2)sin^(2)x=x^(2)+x^(-2);0

The equation 2"cos"^(2)x/2sin^(2)x=x^(2)+x^(-2),0ltxle(pi)/2 has

The equation 2cos^(2)((x)/(2))sin^(2)x=x^(2)+x^(-2),0

The equation 2^(1+cos2x)*sin^(2)x+2sin^(2)2x+2cos2x=2 is satisfied for -

The equation 2 "cos"^(2)((x)/(2))"sin"^(2) x = x^(2) + (1)/(x^(2)), 0 le x le (pi)/(2) has