If A=` [{:(-5,1,3),(7,1,-5),(1,-1,1):}]"and B"=[{:(1,1,2),(3,2,1),(2,1,3):}]`, find the products AB and BA and hence solve the system of equations x+y+2z= 1,3x+2y+z=7, 2x+y+3z=2.

A=[{:(-5,1,3),(7,1,-5),(1,-1,1):}]and B=[{:(1,1,2),(3,2,1),(2,1,3):}] then find AB. Hence, solve the system of equation {:(x+y+2z=1),(3x+2y+z=7),(2x+y+3z=2):}}

If A=[[-3,-5,1],[-3,3,-3],[3,1,-5]] and B=[[1,2,-1],[2,-1,1],[1,1,2]] find the products AB and BA and hence solve the system of equation. x+2y-z=6 2x-y+z=5 x+y+2z=7

The system of equations x +2y+3z=1, x-y+4z=0, 2x+y+7z=1 has

Find the product of matrices A and B, where A= [(-5,1,3),(7,1,-5),(1,-1,1)] and B= [(1,1,2),(3,2,1),(2,1,3)] . Hence, solve the following equations by matrix method: x+y+2z=1, 3x+ 2y + z= 7, 2x+ y + 3z= 2

If A=[{:(3,1,2),(3,2,-3),(2,0,-1):}] , find A^(-1) . Hence, solve the system of equations : 3x+3y+2z=1 , x+2y=4 , 2x-3y-z=5

If A=[{:(1,1,1),(1,0,2),(3,1,1):}] , find A^(-1) . Hence, solve the system of equations : x+y+z=6 , x+2z=7 , 3x+y+z=12