यदि `(log x)/(log 6 ) = (log 36)/(log 6 ) = (log 64)/(log y) `हो , तब x तथा y के मान बताइए।

y = (log x) ^ ((log x) ^ (log x) .... oo)

State, true or false : (i) log 1 xx log 1000 = 0 (ii) (log x)/(log y) = log x - log y (iii) If (log 25)/(log 5) = log x , then x = 2 (iv) log x xx log y = log x + log y

If (log x)/(y-z) = (log y)/(z-x) = (log z)/(x-y) , then prove that xyz = 1 .

Solve for x : (i) (log 81)/(log 27) = x (ii) (log 128)/(log 32) = x (iii) (log 64)/(log 8) = log x (iv) (log 225)/(log 15) = log x

If ("log"x)/(y - z) = ("log" y)/(z - x) = ("log" z)/(x - y) , then prove that xyz = 1.

If 3(log 5 - log 3) - (log 5 - 2 log 6) = 2 - log x, find x.

if log (x+y) = log x + log y , then x= ____