यदि `"cos"^(-1)x+"cos"^(-1)y=(pi)/2`, तो सिद्ध कीजिएः
`"cos"^(-1)x="sin"^(-1)y`

If "cos"^(-1)x+"cos"^(-1)y=(2pi)/(7) , then the value of "sin"^(-1)x+"sin"^(-1)y is

If sin^(-1) x + cos ^(-1) y = (2pi)/5 , then cos^(-1) x + sin ^(-1) y is

If cos^(-1)x+cos^(-1)y=pi/2 then prove that cos^(-1)x=sin^(-1)y

If sin^(-1)x+cos^(-1)y=(2pi)/5," then "cos^(-1)x+sin^(-1)y is

If cos^(-1) x + cos^(-1) y = (pi)/(4) , find the value of sin^(-1) x + sin^(-1) y .

If "Cos"^(-1)x/a+"Cos"^(-1)y/b=(5pi)/12 and "Sin"^(-1)x/a-"Sin"^(-1)y/b=(pi)/12 then (x^(2))/(a^(2))+(y^(2))/(b^(2))=

If sin^(-1)x+cos^(-1)y=(2pi)/(5),"then "cos^(-1)x+sin^(-1)y =

If sin^(-1)x+cos^(-1)y=(2pi)/(5),"then "cos^(-1)x+sin^(-1)y =

If -1<=x,y<=1 such that sin^(-1)x+sin^(-1)y=(pi)/(2), find the value of cos^(-1)x+cos^(-1)y

If -1<=x,y<=1 such that sin^(-1)x+sin^(-1)y=(pi)/(2), find the value of cos^(-1)x+cos^(-1)y