The work function of a metallic surface is 5.01 eV. The photoelectrons are emitted when light of wavelength `2000A` falls on it. The potential difference applied to stop the fastest photoelectrons is

The work function of a metallic surface is 5.01 eV. The photoelectrons are emitted when light of wavelength 2000A falls on it. The potential difference applied to stop the fastes photoelectrons is [h=4.14xx10^(-15)eVs]

The work function of a metallic surface is 5.01 eV . The photo - electrons are emitted when light of wavelength 2000 Å falls on it . The potential difference applied to stop the fastest photo - electrons is [ h = 4.14 xx 10^(-15) eV sec]

The work function of a metallic surface is 5.01 eV . The photo - electrons are emitted when light of wavelength 2000 Å falls on it . The potential difference applied to stop the fastest photo - electrons is [ h = 4.14 xx 10^(-15) eV sec]

The work function of nickle is 5eV . When light of wavelength 2000A^(0) falls on it, emits photoelectrons in the circuit. The the potential difference necessary to stop the fastest electrons emitted is (given h=6.67xx10^(-34) Js )

The work function of the nickel is 5 eV. When a light of wavelength 2000 Å falls on it ,it emits photoelectrons in the circuit .Then, the potential difference necessary to stop the faster electrons emitted is (Given , h=6.67xx10^(-34)J-s)

A metal has work function 5eV. Will this metal emit electrons, when light of wavelength 400 nm falls on it?