In Young's double slit experiment, the intensity at a point where the path difference is `lamda/6` (`lamda` is the wavelength of light) is I. if `I_(0)` denotes the maximum intensities, then `I//I_(0)` is equal to

In a Young's double slit experiment, the intensity at a point where the path difference is (lamda)/6 ( lamda - wavelength of the light) is 1. If I_(0) denotes the maximum intensity, then I/(I_(0)) is equal to

In a Young's double slit experiment the intensity at a point where tha path difference is (lamda)/(6) ( lamda being the wavelength of light used) is I. If I_0 denotes the maximum intensity, (I)/(I_0) is equal to

In a Young's double slit experiment the intensity at a point where tha path difference is (lamda)/(6) ( lamda being the wavelength of light used) is I. If I_0 denotes the maximum intensity, (I)/(I_0) is equal to

In a Young's double slit experiment the intensity at a point where tha path difference is (lamda)/(6) ( lamda being the wavelength of light used) is I. If I_0 denotes the maximum intensity, (I)/(I_0) is equal to

In a Young's double slit experiment,the intensity at a point,where the path difference is lambda//6 ( lambda being the wabelength of the light used) is I .If I_0 denotwes the maximum intensity,then I//I_0 is equal to

In a Young's double slit experiment the intensity at a point where the path difference is (lambda)/(6)(lambda being the wavelength of the light used) is I. If I_(0) denotes the maximum intensity then (I)/(I_(0))=…

In young double slit experiment, the intensity at a point where path difference is lamda/6 is l. IF l_0 denotes the maximum intensity l/l_0 .

The wavelength of the light used in Young's double slit experiment is lamda . The intensity at a point on the screen where the path difference is (lamda)/(6) is I . I_(0) mdenotes the maximum intensity then the ration of I and I_(0) is