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If k, 2k - 1 and 2k +1 are in the arithm...

If `k, 2k - 1` and `2k +1` are in the arithmetic progression then `k`

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Knowledge Check

  • Let (1+x^(2))^(2) (1+x)^(n) +sum_(k=0)^(n+4) a_(k)x^(k) If a_(1),a_(2) and a_(3) are in arithmetic progression, then n is

    A
    6
    B
    4
    C
    3
    D
    2

  • If a_(1),a_(2),a_(3),…a_(n+1) are in arithmetic progression, then sum_(k=0)^(n) .^(n)C_(k.a_(k+1) is equal to

    A
    `2^(n)(a_(1)+a_(n+1))`
    B
    `2^(n-1)(a_(1)+a_(n+1))`
    C
    `2^(n+1)(a_(1)+a_(n+1))`
    D
    `(a_(1)+a_(n+1))`

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