`16^(log_(16)25)`= ______

2 ^(16-log_(2)1024) = ______

log_(2)[log_(4)(log_(10)16^(4)+log_(10)25^(8))] simplifies to :

log_(2)[log_(4)(log_(10)16^(4)+log_(10)25^(8))] simplifies to :

The value of log_(16)root(5)(64) = ______.

log_(2)16=…………

if log_(16)25 = k log_(2)5 then k = _____

log_(16)3.log_(17)4,log_(9)17 =_______

25/16 =__

The number of real values of the parameter k for which (log_(16)x)^(2) = log_(16) x+ log_(16) k = 0 with real coefficients will have exactly one solution is

The number of real values of the parameter k for which (log_(16)x)^(2) - log_(16) x+ log_(16) k = 0 with real coefficients will have exactly one solution is