If `x/a = y/b = z/c `, then show that ` (x^(2)-yz)/(a^(2)-bc) = (y^(2)-zx)/(b^(2) - ca) = (z^(2)-xy)/(c^(2)-ab)`

a(y+z)=x,b(z+x)=y,c(x+y)=z prove that (x^(2))/(a(1-bc))=(y^(2))/(b(1-ca))=(z^(2))/(c(1-ab))

If x + y + z = 0 , then the value of (x^2)/(yz) + (y^2)/(zx) + (z^2)/(xy) is:

Show that |(x,x^(2),yz),(y,y^(2),zx),(z,z^(2),xy)|=(x-y)(y-z)(z-x)(xy+yz+zx)

If x= b+c, y=c+a, z=a+b , then find the value of (x^2 + y^2 + z^2 -yz - zx-xy)/( a^(2) + b^(2) + c^(2) - bc - ca - ab)

If (x^2-yz)/a=(y^2-zx)/b=(z^2-xy)/c , show that (a+b+c)(x+y+z)=(ax+by+cz).

Factorise : x^(2)+y^(2)+z^(2)-xy-yz-zx

If ax+cy+bz=X, cx+by+az=Y, bx+ay+cz=Z, show that (a^(2)+b^(2)+c^(2)-bc-ca-ab)(x^(2)+y^(2)+z^(2)-yz-zx-xy)=X^(2)+Y^(2)+Z^(2)-YZ-ZX-XY