The potential energy `U` in joule of a particle of mass `1 kg` moving in `x-y` plane obeys the law`U = 3x + 4y`, where `(x,y)` are the co-ordinates of the particle in metre. If the particle is at rest at `(6,4)` at time `t = 0` then :

The potential energy varphi , in joule, of a particle of mass 1kg , moving in the x-y plane, obeys the law varphi=3x+4y , where (x,y) are the coordinates of the particle in metre. If the particle is at rest at (6,4) at time t=0 , then

The potential energy varphi , in joule, of a particle of mass 1kg , moving in the x-y plane, obeys the law varphi=3x+4y , where (x,y) are the coordinates of the particle in metre. If the particle is at rest at (6,4) at time t=0 , then

The potential energy phi in joule of a particle of mass 1 kg moving in x-y plane obeys the law, phi=3x + 4y . Here, x and y are in metres. If the particle is at rest at (6m, 8m) at time 0, then the work done by conservative force on the particle from the initial position to the instant when it crosses the x-axis is .

The potential energy phi in joule of a particle of mass 1 kg moving in x-y plane obeys the law, phi=3x + 4y . Here, x and y are in metres. If the particle is at rest at (6m, 8m) at time 0, then the work done by conservative force on the particle from the initial position to the instant when it crosses the x-axis is . a) 25 J b) 25 J c) 50 J d) - 50 J

The potential energy of a particle of mass 2 kg moving in a plane is given by U = (-6x -8y)J . The position coordinates x and y are measured in meter. If the particle is initially at rest at position (6, 4)m, then