Normal is drawn to the ellipse `x^2/27+y^2-1` at a point `(3sqrt3 cos theta, sin theta)` where `theta < theta < pi/2` The value of such that the area of the triangle formed by normal and coordinate axes is maximum is

A normal is drawn to the ellipse (x^(2))/(9)+y^(2)=1 at the point (3cos theta, sin theta) where 0lt theta lt(pi)/(2) . If N is the foot of the perpendicular from the origin O to the normal such that ON = 2, then theta is equal to

A normal is drawn to the ellipse (x^(2))/(9)+y^(2)=1 at the point (3cos theta, sin theta) where 0lt theta lt(pi)/(2) . If N is the foot of the perpendicular from the origin O to the normal such that ON = 2, then theta is equal to

A tangent is drawn to the ellipse (x^(2))/( 27 ) +y^(2) =1 at the point (3sqrt3 cos theta, sin theta) "where" 0 lt theta lt (pi )/(2) then the sum of the intercepts of the tangent with the coordinate axes is least when theta =

A tangent is drawn to the ellipse (x^(2))/(27)+y^(2)=1 at the point (3 sqrt(3) cos theta sin theta) where 0 lt theta lt (pi)/(2) . The sum of intecepts of the tangents with the coordinates axes is least when theta equals

Let a tangent be drawn to the ellipse x^2/(27) +y^2=1" at "(3sqrt3 cos theta, sin theta)," where "theta in (0,pi/2) , Then the value of theta such that the sum of intercepts on axes made by this tangent is minimum is equal to :

A tangent is drawn to the ellipse (x^(2))/(27)+y^(2)=1 at (3sqrt(3)cos theta,sin theta) where theta varepsilon(0,(pi)/(2)) .Then find the value of theta such that the sum of intercepts on the axes made by this tangent is minimum.

Tangent is drawn to ellipse (x^(2))/(27) + y^(2) = "1 at" (3 sqrt(3) cos theta, sin theta) [where theta in (0, pi//2) ]. Then the value of theta such that sum of intercepts on axes made by this tangent is minimum, is

Tangent is drawn to ellipse (x^(2))/(27)+y^(2)=1 at (3sqrt(3)cos theta,sin theta) Iwhere theta in(0,(pi)/(2))] Then the value of theta such that sum of intercepts on axes made by this tangent is mintercepts on (pi)/(6)(c)(pi)/(8)(d)(pi)/(4)

If beta is one of the angles between the normals to the ellipse, x^2+3y^2=9 at the points (3 cos theta, sqrt(3) sin theta)" and "(-3 sin theta, sqrt(3) cos theta), theta in (0,(pi)/(2)) , then (2 cos beta)/(sin 2 theta) is equal to:

If beta is one of the angles between the normals to the ellipse, x^2+3y^2=9 at the points (3 cos theta, sqrt(3) sin theta)" and "(-3 sin theta, sqrt(3) cos theta), theta in (0,(pi)/(2)) , then (2 cot beta)/(sin 2 theta) is equal to: