A 'd' block metal ion has magnetic moment of `1.7332 BM` .The number of unpaired electrons are

A transition metal compound has a magnetic moment of 3.9 BM. Calculate the number of unpaired electrons in the compound.

A compound of a metal ion M^(X+)(z=24) has a spin only magnetic moment of sqrt(15)B.M. . The number of unpaired electrons in the compound are

A compound of a metal ion M^(X+)(z=24) has a spin only magnetic moment of sqrt(15)B.M. . The number of unpaired electrons in the compound are

A comapound in which a metal ion M^(x+)(Z=25) has a spin only magnetic moment of sqrt24 BM The number of unpaired electrons in the compound and the oxidation state of the metal ion respectively are

A complex compound of chromium has magnetic moment 3.83 BM. Calculate the number of unpaired electrons.

Magnetic moment of M^(x+) is sqrt(24)BM . The number of unpaired electrons in M^(x+) is.

A metal ion from the first transition has a magnetic moment of 3.87 B.M. How many unpaired electrons are expected to be present in the ion

A compound in which a metal ion \(M^{x+}\)(Z=25) has a spin only magnetic moment of \(\sqrt{24}\)BM.The number of unpaired electrons in the compound and the oxidation state of the metal ion are respectively.

The substances which contain species with unpaired electrons in their orbitals behave as paramagnetic substances. Such substances are weakly attracted by the magnetic field. The paramagnetism is expressed in terms of magnetic moment. The magnetic moment is related to the number of unpaired electrons according to the following relation : Magnetic moment, mu = sqrt(n(n+2)) B.M. Where .n. = number of unpaired electrons. B.M. stands for Bohr magneton, a unit of magnetic moment. An ion of a d-block elements has magnetic moment 5.92 B.M. Select the ion among the following.