`sec (45^@+A) sec (45^@ -A) =` (i)`sec2A` (ii)`cos2A` (iii)`2cos2A` (iv) `2sec2A`

Prove that: sec(45^(@)+A)sec(45^(@)-A)=2sec2A

Prove that: sec(45^(@)+A)sec(45^(@)-A)=2secA

(sin2A) / (sin A) - (cos2A) / (cos A) = sec A

sec^(2)A(1+sec2A)=2sec2A

(1+sec A)/(sec A)=(sin^(2)A)/(1-cos A)

(1 + sec A ) / ( sec A ) = ( sin ^ 2 A ) /( 1 - cos A )

(tan45^(@)+cot45^(@))+sec^(2)45^(@)= ………….

From the following figure, find the values of : (i) cos A (ii) cosec A (iii) tan^(2)A - sec^(2)A (iv) sin C (v) sec C (vi) cot^(2) C - (1)/(sin^(2)C)

(1 + cot A + tan A) (sin A-cos A) = (sec A) / (cos ec ^ (2) A) - (cos ecA) / (sec ^ (2) A)

(1 + cot A + tan A) (sin A-cos A) = (sec A) / (cos ec ^ (2) A) - (cos ecA) / (sec ^ (2) A)