" Dne root of the equalion "(x+1)(x+3)(x+2)(x+4)=120" is "

One root of the equation (x+1)(x+3)(x+2)(x+4)=120is:

Solve the equations: (x+1)(x+2)(x+3)(x+4)=120

Find number of integer roots of equation x(x+1)(x+2)(x+3)=120

Solve :(x+1)(x+2)(x+3)(x+4)=120

x(x+1)(x+2)(x+3)=120:x=

The number of roots of equation (((x-1)(x-3))/((x-2)(x-4))-e^(x)) (((x+1)(x+3))/((x+2)(x+4))-e^(-x)) (x^(3)-cos x)=0 :

The number of roots of equation (((x-1)(x-3))/((x-2)(x-4))-e^(x))(((x+1)(x+3))/((x+2)(x+4))-e)(-x^(3)-cos x)=0

The roots of the equation (x+(1)/(x))^(2)=4+(3)/(2)(x-(1)/(x)) are

The roots of the equation,(x^(2)+1)^(2)=x(3x^(2)+4x+3) are given by -

x_1 and x_3 are the roots of the equation Ax ^2 - 4x +1=0 and x_2 and x_4 =0 are the roots of the requation Bx^2 - 6x + 1=0 if x_1 , x_2 , x_3 ,x_4 form a H.P , then (A,B) =