How many mL of 22.4 volume `H_(2)O_(2)` is required to oxidise 0.1 mol of `H_(2)S` gas to S ?

Volume of '10 volume' H_(2)O_(2) required to convert 0.01 mol PbS into "PbSO"_(4) is -

How many moles of H_(2)SO_(4) are requried to produce 1 " mol of " H_(2)S when KI reacts with H_(2)SO_(4) producing I_(2) and H_(2)S ?

How many moles of H_(2)SO_(4) are requried to produce 1 " mol of " H_(2)S when KI reacts with H_(2)SO_(4) producing I_(2) and H_(2)S ?

KI reacts with H_(2)SO_(4) producing I_(2) and H_(2)S the volume of 0.2 M H_(2)SO_(4) required to produce 0.1 " mol of " H_(2)S is

KI reacts with H_(2)SO_(4) producing I_(2) and H_(2)S the volume of 0.2 M H_(2)SO_(4) required to produce 0.1 " mol of " H_(2)S is

H_(2)O_(2) is marked 22.4 volume. How much of it is required to oxidise 3.5 g H_(2)S gas?

Manganese ions (Mn^(2+)) can be oxidised by Persulphate ions S_(2)O_(8)^(2-) according to the following half-equations, S_(2)O_(8)^(2-)+2e^(-) to 2SO_(4)^(2-) Mn^(2+)+4H_(2)O to MnO_(4)^(-)+4H_(2)O to MnO_(4)^(-)+8H^(+)+5e^(-) How many moles of S_(2)O_(8)^(2-) are required to oxidise 1mole of Mn^(2+) ?

Manganese ions (Mn^(2+)) can be oxidised by Persulphate ions S_(2)O_(8)^(2-) according to the following half-equations, S_(2)O_(8)^(2-)+2e^(-) to 2SO_(4)^(2-) Mn^(2+)+4H_(2)O to MnO_(4)^(-)+4H_(2)O to MnO_(4)^(-)+8H^(+)+5e^(-) How many moles of S_(2)O_(8)^(2-) are required to oxidise 1mole of Mn^(2+) ?