Calculate the volume, mass and number of molecules of hydrogen liberated when 230 g of sodium reacts with excess of water at STP (atomic masses of Na = 23U, O = 16 U and H = 1U).

Calculate the volume, mass and number of molecules of hydrogen liberated when 230 g of sodium reacts with excess of water at STP. (atomic masses of Na = 23U, O = 16U, and H = 1U) the balanced equation for the above reaction is {:(2Na_((s))+2H_(2)O_((l)),,to2NaOH_((aq)) +H_(2(g))+H_(2(g))uparrow),((2xx23)U+ 2(2xx1 +1 xx 16)U,,to2(23+16+1)U+(2xx1)U),(46 U + 36U,,to80U + 2U),(or46g + 36g ,, to 80 g + 2 g):}

What is the quantity of hydrogen gas liberated when 46 g sodium reacts with excess ethanol ? (Given atomic mass of Na = 23 )

Calculate the following: The volume & number of moles of oxygen liberated at s.t.p. when 5.2 gm. of sodium peroxide [Na_2 O] reacts with water. 2Na_2 O_2 + 2H20 to 4NaOH + O_2 [Na=23, O=16]

Molecular mass of HNO_3 (Atomic masses of H=1U, N=14U, O=16U)-

What is the mass of 0.5 mole of wate (H_(2)O) . (Atomic masses : H = 1 u, O = 16 u )