[" 27.Calculate the centripetal acceleration of a point "],[" on the equator of earth due to the rotation of "],[" earth about its own axis.Radius of earth "],[=6400km.]

Calculate the centripetal acceleation of a point on the equator of earth due to the rotatin of earth about its wn axis . Radius of earth = 6400 km .

How is acceleration due to gravity affected by rotation of earth about its axis ?

What is the difference in the values of acceleration due to gravity at the polar region and at the equator due to the diurnal motion of the earth ? Radius of the earth=6400 km.

What is the linear velocity of a person at equator of the earth due to its spinning motion? (Radius of the earth = 6400 km.)

What is the linear velocity of a person at equator of the earth due to its spinning motion? (Radius of the earth = 6400 km.)

Calculate the rotation kinetic energy of the earth about its own axis. (M= 6 times 10^24 kg and R = 6400km)

What is the linear velocity of a person at equator of the earth due to its spinning motion? (Radius of the earth =6400km )

Find the value of acceleration due to gravity in a mine at a depth of 80 km from the surface of the earth . Radius of the earth = 6400 km .

Find the value of acceleration due to gravity in a mine at a depth of 80 km from the surface of the earth . Radius of the earth = 6400 km .