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Use the work-energy theorem to find the ...

Use the work-energy theorem to find the force required to accelerate an electron `( m = 9.11 xx 10^(-31) kg)` from rest to a speed of `1.50xx10^(7)`m/s in a distance of 0.0125 m.

A

`8.20xx10^(-15)N`

B

`8.20xx10^(-17)N`

C

`5.47xx10^(-22)N`

D

`1.64xx10^(-14)N`

Text Solution

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The correct Answer is:
To find the force required to accelerate an electron from rest to a speed of \(1.50 \times 10^7 \, \text{m/s}\) over a distance of \(0.0125 \, \text{m}\) using the work-energy theorem, we can follow these steps: ### Step 1: Understand the Work-Energy Theorem The work-energy theorem states that the work done by the net force acting on an object is equal to the change in its kinetic energy. Mathematically, it can be expressed as: \[ W = \Delta KE \] where \(W\) is the work done and \(\Delta KE\) is the change in kinetic energy. ### Step 2: Calculate the Change in Kinetic Energy The change in kinetic energy can be calculated using the formula: \[ \Delta KE = KE_{\text{final}} - KE_{\text{initial}} \] Since the electron starts from rest, its initial kinetic energy \(KE_{\text{initial}} = 0\). The final kinetic energy is given by: \[ KE_{\text{final}} = \frac{1}{2} m v^2 \] where \(m\) is the mass of the electron and \(v\) is its final speed. ### Step 3: Substitute the Values Given: - Mass of the electron, \(m = 9.11 \times 10^{-31} \, \text{kg}\) - Final speed, \(v = 1.50 \times 10^7 \, \text{m/s}\) Now, substituting these values into the kinetic energy formula: \[ KE_{\text{final}} = \frac{1}{2} \times (9.11 \times 10^{-31}) \times (1.50 \times 10^7)^2 \] ### Step 4: Calculate the Kinetic Energy Calculating \(v^2\): \[ (1.50 \times 10^7)^2 = 2.25 \times 10^{14} \] Now substituting back: \[ KE_{\text{final}} = \frac{1}{2} \times (9.11 \times 10^{-31}) \times (2.25 \times 10^{14}) = 1.024875 \times 10^{-16} \, \text{J} \] ### Step 5: Calculate the Work Done Since the initial kinetic energy is zero, the work done \(W\) is equal to the final kinetic energy: \[ W = KE_{\text{final}} = 1.024875 \times 10^{-16} \, \text{J} \] ### Step 6: Relate Work Done to Force The work done can also be expressed in terms of force and distance: \[ W = F \cdot d \] where \(F\) is the force and \(d\) is the distance over which the force is applied. Rearranging gives: \[ F = \frac{W}{d} \] ### Step 7: Substitute the Values to Find Force Given the distance \(d = 0.0125 \, \text{m}\): \[ F = \frac{1.024875 \times 10^{-16}}{0.0125} \] Calculating this gives: \[ F = 8.199 \times 10^{-15} \, \text{N} \] ### Final Answer The force required to accelerate the electron is approximately: \[ F \approx 8.20 \times 10^{-15} \, \text{N} \] ---
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