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A motorist driving a 1000-kg car wishes ...

A motorist driving a 1000-kg car wishes to increase her speed from 20 m/s to 30 m/s in 5 s. Determine the horse-power required to accomplish this increase. Neglect friction .

A

70hp

B

90hp

C

30hp

D

80hp

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will follow these calculations: ### Step 1: Calculate the acceleration The formula for acceleration \( a \) is given by: \[ a = \frac{v_f - v_i}{t} \] Where: - \( v_f = 30 \, \text{m/s} \) (final velocity) - \( v_i = 20 \, \text{m/s} \) (initial velocity) - \( t = 5 \, \text{s} \) (time) Substituting the values: \[ a = \frac{30 \, \text{m/s} - 20 \, \text{m/s}}{5 \, \text{s}} = \frac{10 \, \text{m/s}}{5 \, \text{s}} = 2 \, \text{m/s}^2 \] ### Step 2: Calculate the force Using Newton's second law, the force \( F \) can be calculated as: \[ F = m \cdot a \] Where: - \( m = 1000 \, \text{kg} \) (mass of the car) - \( a = 2 \, \text{m/s}^2 \) (acceleration) Substituting the values: \[ F = 1000 \, \text{kg} \cdot 2 \, \text{m/s}^2 = 2000 \, \text{N} \] ### Step 3: Calculate the displacement Using the kinematic equation: \[ v_f^2 = v_i^2 + 2as \] Rearranging for displacement \( s \): \[ s = \frac{v_f^2 - v_i^2}{2a} \] Substituting the values: \[ s = \frac{(30 \, \text{m/s})^2 - (20 \, \text{m/s})^2}{2 \cdot 2 \, \text{m/s}^2} \] Calculating: \[ s = \frac{900 - 400}{4} = \frac{500}{4} = 125 \, \text{m} \] ### Step 4: Calculate the work done Work \( W \) is given by: \[ W = F \cdot s \] Substituting the values: \[ W = 2000 \, \text{N} \cdot 125 \, \text{m} = 250000 \, \text{J} \] ### Step 5: Calculate the power Power \( P \) is given by: \[ P = \frac{W}{t} \] Substituting the values: \[ P = \frac{250000 \, \text{J}}{5 \, \text{s}} = 50000 \, \text{W} \] ### Step 6: Convert power to horsepower To convert watts to horsepower, use the conversion factor \( 1 \, \text{hp} = 746 \, \text{W} \): \[ \text{Horsepower} = \frac{50000 \, \text{W}}{746 \, \text{W/hp}} \approx 67.07 \, \text{hp} \] ### Final Answer The horsepower required to accomplish this increase in speed is approximately **67 hp**. ---
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