If the angles between assymptotes of hyperbola `x^2/a^2-y^2/b^2=1` is `2theta` then `e=sectheta`

If the angles between assymptotes of hyperbola (x^(2))/(a^(2))-(y^(2))/(b^(2))=1 is 2 theta then e=sec theta Also the acute angle between its assymptotes is theta=tan^(-1)(2a(b)/(a^(2)-b^(2)))

The angle between the asymptotes of the hyperbola x^(2)-y^(2)=2 is

The angle between the asymptotes of the hyperbola (x^2)/(a^2)-(y^2)/(b^2)=1 is

Angle between the asymptotes of a hyperbola is x^(2)-3y^(2)=1 is

The angle between the asymptotes of the hyperbola x^(2) -3y^(2) =1 is

The angle between the asymptotes of the hyperbola x^(2)//a^(2)-y^(2)//b^(2)=1 is

The angle between the asymptotes of the hyperbola x^(2)//a^(2)-y^(2)//b^(2)=1 is

The angle between the asymptotes of the hyperbola 3 x^(2)-y^(2)=3 is

The angle between the asymptotes of the hyperbola x^(2) -3y^(2) =3 is