" (ii) "quad (3^(-5)times10^(-5)times125)/(5^(-7)times6^(-5))

3^(-5)times10^(-4)times(5^(4))/(5^(2))times6^(-5)=

(5)/(7)times(5)/(7)times(5)/(7)times(5)/(7)

solve it : (ii) (-3)/(5)times(-3)/(5)times(-3)/(5)times(-3)/(5) (iii) (-9)/(2)times(4)/(2)times(-4)/(2)times(-4)/(2)times(-4)/(2)times(-4)/(2) (iv) (-5)/(3)times(-5)/(3)times(-5)/(3)times(-5)/(3) (v) (-6)/(2)times(-6)/(2)times(-6)/(2)times(-6)/(2)times(-6)/(2)

Simplify. (i) (25 xx t^(-4))/(5^3 xx 10 xx t^(-8)) (t != 0) (ii) (3^(-5) xx 10^(-5) xx 125)/(5^(-7) xx 6^(-5))

i)25xx(t^(-4))/(5^(3)xx10xx t^(-8))ii)3^(-5)xx10^(-5)xx(125)/(5^(-7)xx6^(-5))

Simplify and express the result in power notation with positive exponent: (a) "7^(5)times7^(3)-:7^(-4), (b) 6^(11)times6^(3)times6^(-5)

" (f) (5^(6)times a^(7))/(5^(2)times a^(3)times(10)^(0))

[8^(-2/3)times2^(1/2)times25^(-5/4)]÷[32^(-2/5)times125^(-5/6)] =sqrt2

((5^(3))^(-2)times(5^(2))^(-3)times(6)^(5))/((2)^(3)times(3)^(2)times(5)^(5))