`(dy)/(dx)doty=cos(sinx^3)`

Solve: (dy)/(dx)+y/x=cos x+(sinx)/x

Solve: (dy)/(dx)+y=cos x-sinx

Solve the differential equation: cos^3x(dy)/(dx)+ycosx=sinx

(dy)/(dx)tany=sinx+cosx

(dy)/(dx)+(y)/(x)=sinx

(dy)/(dx ) + 2y =sinx

x sinx(dy)/(dx)+(x cos x+sinx)y=sinx

Find (dy)/(dx), y= x^(sin x) + (sinx)^(cos x)

"If "y=(sinx)^(cosx)+(cosx)^(sinx)", prove that "(dy)/(dx)=(sinx)^(cosx).[cot x cos x-sin x(log sinx)]+(cosx)^(sinx).[cosx(log cos x)-sinx tanx].