`underset(x to oo)lim ((x+1)^(10)+(x+2)^(10)+...+(x+10)^(10))/(x^(10)+10^(10))=...`

Lt_(x to oo) ((x+1)^(10)+(x+2)^(1)....+(x+50)^(10))/(x^(10)-10^(10))

If underset(xrarroo)"lim"((1+x)^(10)+(x+2)^(10)+....+(x+100)^(10))/(x^(10)+10^(10)) =K^(2) , then the value of K will be -

lim_(xtooo) ((x+1)^(10)+(x+2)^(10)+...+(x+100)^(10))/(x^(10)+10^(10)) is equal to

lim_(xtooo) ((x+1)^(10)+(x+2)^(10)+...+(x+100)^(10))/(x^(10)+10^(10)) is equal to

lim_(x rarr oo x rarr oo)((x+1)^(10)+(x+2)^(10)+...+(x+100)^(10))/(x^(10)+10^(10))

Evaluate : underset(x to oo)(Lt)((x+1)^10+(x+2)^10+.....+(x+100)^10)/x^10

lim_(x rarr oo) ((x+2)^(10)+(x+4)^(10)+...+(x+20)^(10))/(x^(10)+1)= ______.

lim_ (x rarr oo) ((x + 2) ^ (10) + (x + 4) ^ (10) ++ (x + 20) ^ (10)) / (x ^ (10) +1) =

Evaluate : lim_(x to infty) ((x+1)^10+(x+2)^10+....+(x+100)^10)/(x^10+10^10)

lim_(xrarroo)((x+1)^(10)+(x+2)^(10)+...+(x+100)^(10))/(x^(10)+10^(10)) is equal to (a) 0 (b) 1 (c) 10 (d) 100