Defferentinate `y=sin(x^(2))`

solution of the differential equation (x^(2)sin^(3)y-y^(2)cos x)dx+(x^(3)cos y sin^(2)y-2y sin x)dy=0 is

Show that sin(x+y)sin(x-y)= sin^2 x -sin^2 y .Hence prove that sin(x+y)sin(x-y)+sin(y+z)sin(y-z) +sin(z+x)sin(z-x)=0

the value of lim_(x rarr y)(sin^(2)x-sin^(2)y)/(x^(2)-y^(2)) equals

Solution of differential equation (2x cos y + y ^ (2) cos x) dx (2y sin xx ^ (2) sin y) dx = 0 is (a) x ^ (2) cos y + y ^ (2) sin x = C (b) x cos yy sin x = C (c) x ^ (2) cos ^ (2) y + y ^ (2) sin ^ (2) x = C (d) x cos y + y sin x = C

y=sqrt [[sin x + sqrt{{sin x + sqrt ((sin x +1…)}}] or y = sqrt(sin x +y) or y^2 = sin x + y Differentiating w.r. to x.

Draw the graph of y=sin x and y=sin . (x)/(2) .

Draw the graph of y=sin x and y=sin . (x)/(2) .

Draw the graph of y=sin x and y=sin . (x)/(2) .

If sin^(2)x+cos^(2)y=1 , show that dy/dx=(sin2x)/(sin 2y)

Plot y=sin x and y=sin2x