`h=-4.9t^(2)+25t`
The equation above expresses the approximate height h, in meters, of a ball t seconds after it is launched vertically upward from the ground with an initial velocity of 25 meters per second. After approximately how many seconds will the ball hit the ground?

h(t)=144t-16t^(2) The function above represents the height, in feet, a ball reaches t seconds after it is tossed in the air from groud level. a. What is the maximum height of the ball? b. After how many seconds will the ball hit the ground before rebounding?

h=-16t^(2) + vt + k The equation above gives the height h, in feet, of a ball t seconds after it is thrown straight up with an initial speed of v feet per second from a height of k feet. Which of the following gives v in terms of h, t, and k ?

A ball is thrown vertically upwards from the top of tower of height h with velocity v . The ball strikes the ground after time.

A ball is thrown vertically upwards from the top of tower of height h with velocity v . The ball strikes the ground after time.

The approximate height h of an object launched vertically upward after an elapsed time t is represented by the equation h=(1)/(2)at^(2)+v_(o)t+h_(o) , where a is acceleration due to gravity, v_(o) is the object's initial velocity, and h_(o) is the objects initial height. the table aabove gives the acceleration due to gravity on Earth's moon and several planets. If two identical objects launched vertically upward at an initial velocity of 40m/s from the surfaces of Mars and Earth's moon approximately how many more seconds will it take for the moon projectile to return to the ground than the Mars projectile?

h(t)=-4.9t^(2)+68.6t The function above gives the height of a model rocket, in meters, t seconds after it is launched from ground level. What is the maximum height, to the nearest meter, attained by the model rocket?

A ball is thrown vertically upwards with velocity of 25m/s from the top of a tower of height 30m . How long will if travel before it hits the ground ?

A projectile is fired vertically upwards with an initial velocity u . After an interval of T seconds a second projectile is fired vertically upwards, also with initial velocity u .

A stone projected vertically up from the ground reaches a height y in its path at t_1 seconds and after further t_2 seconds reaches the ground. The height y is equal to