The work function of cesium is 2eV. Explain this statement.

The work function of cesium is 2.14 eV. Find (a) the threshold frequency for cesium, and (b) the wavelength of the incident light if the photo current is brought to zero by a stopping potential 0.60 V. Given h=6.63xx10^(-34)Js .

The work function of caesium is 2.14 eV. Find the threshold frequency for caesium .

The work function of cesium is 2.14 eV. The threshold freqency of caesium is

The work function of cesium is 2.14 eV. The threshold freqency of caesium is

The work function of cesium is 2.27 eV. The cut-off voltage wich stops the emission of electrons from a cesium cathode irradiated with light of 600 nm wavelength is

The work function for cesium is 1.8 eV. A light of wavelength 5000 Å is incident on it. Calculate (i) maximum kinetic energy of emitted electrons, (ii) threshold frequency and threshold wavelength and (iii) maximum velocity of the emitted electrons

The work function of caesium is 2.14 eV . Find Threshold frequency for caesium