Recommended Questions
- sin3A+sin2A-sinA = 4sinA*cos(A/2)*cos((3A)/(2))
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- sin3A+sin2A-sin A=4sin A*cos((A)/(2))*cos((3A)/(2))
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- Let a=(pi)/(7) Show that sin^(2)3a+sin^(2)a=sin2a sin3a
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- Prove that sinA+sin2A+sin4A+sin5A=4 (cosA/2)(cos3A/2)sin3A
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- Prove that: sinA+sin2A+sin4A+sin5A= 4sin3A. cosA/2.cos(3A)/(2)
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- सिद्ध कीजिए की (sin 11A * sin A+sin 7A*sin3A)/(cos 11A*sinA+cos7A*sin ...
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- Prove that (sin5A- sin3A)/(cos 5A +cos 3A)= tanA
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- sin3A+sin2A-sinA=4sinA"cos"(A)/(2)"cos"(3A)/(2).
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- सिद्ध कीजिए कि(cos3A+sin3A)/(cosA-sinA)=1+2sin2A.
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