Stone of mass 1 kg tied to the end of a string of length 1m , is whirled in horizontal circle with a uniform angular velocity `2 rad s^(-1)`. The tension of the string is (in newton)

A stone of mass 1 kg tied at the end of a string of length 1 m and is whirled in a verticle circle at a constant speed of 3 ms^(-1) . The tension in the string will be 19 N when the stone is (g=10 ms^(-1))

A stone of mass 1 kg tied at the end of a string of length 1 m and is whirled in a verticle circle at a constant speed of 3 ms^(-1) . The tension in the string will be 19 N when the stone is (g=10 ms^(-1))

A stone of mass 50 g is tied to the end of a string 2 m long and is set into rotation in a horizontal circle with a uniformspeed of 2 m//s . Then tension in the string is

If a stone tied at the one end of a string of length 0.5 m is whirled in a horizontal circle with a constant speed 6 ms^(-1) , then the acceleration of the stone is

A stone of mass 250 gram , attached at the end of a string of length 1.25 m is whirled in a horizontal circle at a speed of 5 m/s . What is the tension in the string ?

A stone is tied to the end of a string of length 1 and whirled in a horizental circle. When the string breaks then stone

A stone of mass 2.0 kg is tied to the end of a string of 2m length. It is whirled in a horizontal circle. If the breaking tension of the string is 400 N, calculate the maximum velocity of the stone.

A stone of mass 2.0 kg is tied to the end of a string of 2m length. It is whirled in a horizontal circle. If the breaking tension of the string is 400 N, calculate the maximum velocity of the stone.