Two bodies begin a free fall from rest from the same height 2 seconds apart. How long after the first body begins to fall, the two bodies will be 40 m apart? `("Take g = 10ms"^(-2))`

Two diamonds begin a free fall from rest from the same height, 1.0 s apart. How long after the first diamond begins to fall will the two diamonds be 10 m apart? Take g = 10 m//s^2.

Two diamonds begin a free fall from rest from the same height, 1.0 s apart. How long after the first diamond begins to fall will the two diamonds be 10 m apart? Take g = 10 m//s^2.

Two particles are released from the same height at an interval of 1s . How long aftger the first particle begins to fall will the two particles be 10m apart? ( g=10m//s^(2) )

Two particles are released from the same height at an interval of 1s . How long aftger the first particle begins to fall will the two particles be 10m apart? ( g=10m//s^(2) )

Two bodies begin to fall freely from the same height but the second falls T second after the first. The time (after which the first body begins to fall) when the distance between the bodies equals L is

Two bodies begin to fall freely from the same height but the second falls T second after the first. The time (after which the first body begins to fall) when the distance between the bodies equals L is

Two bodies begin to fall freely from the same height. The second one begins to fall tau s after the first. The time after which the 2st body begins to fall, the distance between the bodies equals to l is