centre at the origin and radius 4

If the point (x ,4) lies on a circle whose centre is at the origin and radius is 5, then x= +-5 (b) +-3 (c) 0 (d) 14

If the point (x,4) lies on a circle whose centre is at the origin and radius is 5, then x=+-5 (b) +-3(c)0(d)14

In the figure, O is the centre of the circle and x^2+y^2=25 is the equation of the circle. Write the equation of the circle whose centre is at the origin and radius is 3. .

C_1 is a circle with centre at the origin and radius equal to 'r' and C_2 is a circle with centre at (3r, 0) and radius equal to 2r. The number of common tangents that can be drawn to the two circle are :

Show that the differential equation of the family of circles having their centres at the origin and radius 'a' is : x+y (dy)/(dx)=0 .

The line y = sqrt3 x +4 touches a circle with centre at the origin. Find the radius of the circle.

If the point (x,4) lies on a circle whose centre is at the origin and the radius is 5, then x = . . . . . .

If the length of the normal for each point on a curve is equal to the radius vector, then the curve (a) is a circle passing through origin (b) is a circle having centre at origin and radius 0 (c) is a circle having centre on x-axis and touching y-axis (iv) is a circle having centre on y-axis and touching x-axis

If the length of the normal for each point on a curve is equal to the radius vector,then the curve (a) is a circle passing through origin (b) is a circle having centre at origin and radius 0 (c) is a circle having centre on x-axis and touching y-axis (iv) is a circle having centre on y-axis and touching x-axis