`sin^2 theta =(x+y)^2/(4xy)` where x,y`in`R gives `theta` if and only if

csc theta=(x^(2)-y^(2))/(x^(2)+y^(2)), where x in R,y in R given real theta if and only if

The given expression sec^2 theta =(4xy)/((x+y)^(2)) is true if and only if :

Prove that sin^2theta=(x+y)^2/(4xy) is possible for real values of x and y only when x = y , y!=0 and x!=0 .

sin^(2) theta = ((x+y)^(2))/(4xy) is true if and only if

sin^2 theta= (4xy)/(x+y)^2 is true if and only if (A) x-y!=0 (B) x=-y (C) x+y!=0 (D) x!=0,y!=0

sin^(2)theta=(4xy)/((x+y)^(2)) is true if and only if (A)x-y!=0(B)x=-y(C)x=y(D)x!=0,y!=0

"sec"^(2) theta = (4xy)/((x + y)^(2)) is true if and only if-

sec^2theta=4xy/(x+y)^2 is true if and only if