If AOB is a diameter of a circle and C is a point on the circle, then `AC^(2)+BC^(2)=AB^(2)`.

AB is a diameter of a circle. C is any point on the circle, angleACB=

AOB is a diameter of a circle with centre O and C is any point on the circle, joining A, C, B, C, and O, C, prove that sin^(2)angleBCO+sin^(2)angleACO=1

AOB is a diameter of a circle with centre O and C is any point on the circle, joining A, C, B, C, and O, C, prove that cosec^(2)angleCAB-1=tan^(2)angleABC .

AB is a diameter of a circle and C is any point on the circumference of the circle, then :

AOB is a diameter of a circle with centre O and C is any point on the circle, joining A, C, B, C, and O, C, prove that tanangleABC=cotangleACO

AB is a diameter of a circle and 'C' is any point on the circumference of the circle .Then

AOB is a diameter of a circle , C is a point on the circle. If angle OBC=60^(@) , then find the value of angleOCA

AOB is a diamter of a circle with centreO, C is any point on the circle If AC = 6cm and BC = 8cm then AB=

AOB is diameter of a circle whose centre is O and C is any point on the circle. Join A and C , B and C and O and C. Show that (sin^2 /_BCO + sin^2 /_ACO) = 1 .