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The volume of 0.2 M NaOH needed to prepa...

The volume of `0.2 M NaOH` needed to prepare a buffer of `pH 4.74` with `50 mL` fo `0.2M` sodium dicholoroacetate acid `(pK_(b) ` of `CH_(3)COO^(-)=9.26)` is `:`

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The Ph of basic buffer mixtures is given by : Ph=Pk_(a)+ log (["Base"])/(["Salt"]) whereas Ph of acidic buffer mixtures is given by : Ph = pK_(a)+"log"(["Salt"])/(["Acid"]) . Addition of little acid or base although shows no appreciable change in Ph for all practical purposes, but sicne the ratio (["Base"])/(["Salt"]) or (["Salt"])/(["Acid"]) changes, a slight decrease or increase in pH results. The volume of 0.2 m NaOH needed to prepare a buffer of pH 4.74 with 50 mL of 0.2 m acetic acid pH_(b) of CH_(3)COO^(-)=9.26 is :

The pH of basic buffer mixtures is given by : pH=pK_(a)+log((["Base"])/(["Salt"])) , whereas pH of acidic buffer mixtures is given by: pH= pK_(a)+log((["Salt"])/(["Acid"])) . Addition of little acid or base although shows no appreciable change for all practical purpose, but since the ratio (["Base"])/(["Salt"]) or (["Salt"])/(["Acid"]) change, a slight decrease or increase in pH results in. The volume of 0.2M NaOH needed to prepare a buffer of pH 4.74 with 50 mL of 0.2M acetic acid is: (pK_(a) of CH_(3)COO^(-)= 9.26)

The pH of a buffer solution prepared by adding 10 mL of 0.1 M CH_(3) COOH and 20 mL 0.1 M sodium acetate will be ( given : pK_(a) of CH_(3)COOH = 4.74 )

The pH of a buffer solution prepared by adding 10 mL of 0.1 M CH_(3) COOH and 20 mL 0.1 M sodium acetate will be ( given : pK_(a) of CH_(3)COOH = 4.74 )

To prepare a buffer solution of pH=4.04, amount of Barium acetate to be added to 100 mL of 0.1 M acetic acid solution [pK_b(CH_(3)COO^(-))=9.26] is:

To prepare a buffer solution of pH=4.04, amount of Barium acetate to be added to 100 mL of 0.1 M acetic acid solution [pK_b(CH_(3)COO^(-))=9.26] is:

The ratio of volumes of CH_(3)COOH 0.1 (N) to CH_(3)COONa 0.1 (N) required to prepare a buffer solution of pH 5.74 is (given : pK_(a) " of " CH_(3) COOH " is " 4.74)