If the origin is shifted to the point (2,-2), the equation to which the equation `(x-2)^(2) + (y+2)^(2)=9` transformed is

Keeping coordinate axes parallel, the origin is shifted to a point (1, –2), then transformed equation of x^2 + y^2 = 2 is -

When (0,0) shifted to (2, -2) the transformed equation of (x - 2)^(2) + (y + 2)^(2) = 9 is

If origin is shifted to the point (a,b) then what will be the transformed equation of the curve (x-a)^(2)+(y-b)^(2)=r^(2) ?

If origin is shifted to the point (a,b) then what will be the transformed equation of the curve (x-a)^(2)+(y-b)^(2)=r^(2) ?

When the origin is shifted to the point (2 , 3) the transformed equation of a curve is x^(2) + 3xy - 2y^(2) + 17 x - 7y - 11 = 0 . Find the original equation of curve.

When (0,0) shifted to (2,-2) the transformed equation of (x-2)^(2)+(y+2)^(2)=9 is

The point to which the origin should be shifted in order to eliminate x and y in the equation 2(x-5)^(2) + 3(y+7)^(2) =10 is