वक्र `x=acos^3theta, y=sin^3theta` के `theta=pi/4` पर अभिलंब की प्रवणता ज्ञात कीजिए

If x=acos^3theta , y=asin^3theta Find (d^2y)/dx^2 .

If x=acos^(3)theta and y=asin^(3)theta , then (dy)/(dx)=

If x=acos^3theta,y=bsin^3theta,fin d(d^3y)/(dx^3) at theta=0.

If x=acos^3theta,y=bsin^3theta,fin d(d^3y)/(dx^3) at theta=0.

If x=acos^3theta,y=a sin^3theta then find (d^2y)/(dx^(2))

If x=acos^3theta,y=a sin^3theta then find (d^2y)/(dx^(2))

If x=acos^3theta,y=bsin^3theta ,fin d (d^3y)/(dx^3) at theta=0.

The equation of the normal to the curve x=a\ cos^3theta,\ \ y=a\ sin^3theta at the point theta=pi//4 is (a) x=0 (b) y=0 (c) x=y (d) x+y=a

If x=acos^3theta,y=bsin^3theta, f i n d (d^3y)/(dx^3) at theta=0.

If x=acos^3theta,y=a sin^3theta, then find the value of d2y/dx2 at θ=π/6