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int e^x [sec x + log ( sec x+ tan x )]dx...

`int e^x [sec x + log ( sec x+ tan x )]dx`

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int sec x log (sec x+ tan x)dx=

int secx. log (sec x+ tan x ) dx

int secx. log (sec x+ tan x ) dx

int e^x sec e^x dx

int e^x sec e^x dx

int sec x log (sec x+tan x) dx.

int x sec x tan x dx=

int (sec x dx)/(log (sec x +tan x)) =

int e^(x)[log (sec x + tan x)+sec x]dx

Integrate the following w.r. t. x: int frac{sec x}{log (sec x + tan x)} dx