A metal surface having a work function `phi = 2.2 xx 10^(-19) J`, is illuminated by the light of wavelengh `1320Å`. What is the maximum kinetic energy ( in eV ) of the emitted photoelectron ? [Take `h = 6.6 xx 10^(-34) Js `]

A metal having work function 4.41xx10^(-19) J is sunjected to a light having wavelength 300nm, then maximum kinetic energy of the emitted photoelectron is ...........xx10^(-21)J

A metal having work function 4.41xx10^(-19) J is sunjected to a light having wavelength 300nm, then maximum kinetic energy of the emitted photoelectron is ...........xx10^(-21)J

If the work function for a certain metal is 3.2 xx 10^(-19) joule and it is illuminated with light of frequency 8 xx 10^(14) Hz . The maximum kinetic energy of the photo-electrons would be (h = 6.63 xx 10^(-34) Js)

If the work function for a certain metal is 3.2 xx 10^(-19) joule and it is illuminated with light of frequency 8 xx 10^(14) Hz . The maximum kinetic energy of the photo-electrons would be (h = 6.63 xx 10^(-34) Js)

The work function of a metal is 1.6 xx 10^(-19) J . When the metal surface is illuminated by the light of wavelength 6400 Å , then the maximum kinetic energy of emitted photo - electrons will be (Planck's constant h = 6.4 xx 10^(-34) Js )

If the work function of a certain metal is 3.2xx10^(-19)J and is it illuminated with light of frequency 8xx10^(14) Hz, the maximum kinetic energy of photo electrons would be (h=6.6xx10^(-34)Js)

The work function of a metal is 1.6 xx 10^-19J . The metal surface is illuminated by light of wavelength 6400overset@ A . What will be the maximum kineticenergy of photoelectrons emitted.

The electric field of certain radiation is given by the equation E = 200 {sin (4pi xx 10^10)t + sin(4pi xx 10^15)t} falls in a metal surface having work function 2.0 eV. The maximum kinetic energy 2.0 eV. The maximum kinetic energy (in eV) of the photoelectrons is [Plank's constant (h) = 6.63 xx 10^(-34)Js and electron charge e = 1.6 xx 10^(-19)C]