if the roots of the equation ` z^(2) + ( p +iq) z + r + is =0` are real wher p,q,r,s, `in` ,R , then determine ` s^(2) + q^(2)r`.

The roots of the equation (q- r) x^(2) + (r - p) x + (p - q)= 0 are

The roots of the equation (x-p) (x-q)=r^(2) where p,q , r are real , are

The roots of the equation (q-r)x^(2)+(r-p)x+(p-q)=0

The roots of the given equation (p - q) x^2 + (q -r ) x + (r - p)=0 are

For a complex number z, the equation z^(2)+(p+iq)z r+" is "=0 has a real root (where p, q, r, s are non - zero real numbers and i^(2) = -1 ), then